Definition:

Any object located in the field of the earth experiences a gravitational pull. Gravitational acceleration is described as the object receiving an acceleration due to the force of gravity acting on it. It is represented by ‘g’ and its unit is m/s2. Gravitational acceleration is a quantity of vector, that is it has both magnitude and direction.

Formula:

Using the following equation, the gravitational acceleration acting on anybody can be explained

\begin{array}{l}g = GM/ (r + h)^{2}\end{array}

Here, G is the universal gravitational constant (G = 6.673×10-11 N.m2/Kg2.)

M is the mass of the body whose gravitational force acts on the given object under certain condition.
r is the planet radius.

h is the height of the object from the body surface.

When the object is on or near the surface of the body, the force of gravity acting on the object is almost constant and the following equation can be used.

\begin{array}{l}g = GM/ r^{2}\end{array}

Derivation:

From Newton’s Second Law of Motion, we can write

\begin{array}{l}F_{g} = GMm / (r + h)^{2}\end{array}

F=ma

Here, F is the force acting on the object.

m is its mass and

‘a’ is the acceleration.

Also, as per Newton’s Law of Gravity, we can write,

It is the gravitational force acting between two bodies lying in the gravitational field of each other. This force acts inwards and is attractive in nature. Each of the two bodies experiences the same force directed towards the other.

Using Newton’s second law of motion, in order to find the acceleration of the body under this condition,

\begin{array}{l}a = F_{g}/m\end{array}

Here, m is the mass of the object for which the gravitational acceleration is to be calculated.

\begin{array}{l}a = g = GMm / (r + h)^{2}m\end{array} \begin{array}{l}g = GM/ (r + h)^{2}\end{array}

Also, the value of g is constant when the object is on or near the surface and there is no considerable change with the height. Hence we can write,

\begin{array}{l}g = gM/r^{2}\end{array}

Real Life examples:

Let us consider a satellite that has to revolve in the upper part of the atmosphere surrounding the Earth. In order to calculate the velocity with which it has to move so as to remain in its path, we must know the gravitational acceleration acting on the object.

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